First, we must determine the total number of valence electrons available. Sulfate contains one Sulfur (S) atom and four Oxygen (O) atoms, and it carries a -2 charge.
Each oxygen atom has 4 pairs of electrons (8 electrons), fulfilling the octet rule. lewis dot structure of so42
Therefore, the real ion is a . There are multiple equivalent resonance structures. In each structure, the two negative charges and the two double bonds are distributed among different pairs of oxygen atoms. The actual ion has: First, we must determine the total number of
(with one double bond to fulfill resonance structures) Therefore, the real ion is a
The arrangement of the four oxygen atoms around the sulfur creates a Tetrahedral geometry.
The Lewis structure for the sulfate ion ($SO_4^2-$) features a central Sulfur atom bonded to four Oxygen atoms. Two of these bonds are double bonds, and two are single bonds (bearing the negative charges). Due to resonance, the double bonds are delocalized across all four oxygen atoms.
Wayne Breslyn (Dr. B.) 4:30 What is the total number of valence electrons in the Lewis structure ... The total number of valence electrons in the Lewis structure of SO42- is 32. This is calculated by adding the valence electrons of... CK-12 Foundation SO42- Resonance Structures - How to Draw Step by Step! Jul 13, 2025 —